(-2x^2^-3/4y^4)^-3

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Solution for (-2x^2^-3/4y^4)^-3 equation: 


D( x )

x < 0

((-2*x^(2^-3))/4)*y^4 = 0

x < 0

((-2*x^(2^-3))/4)*y^4 = 0

((-2*x^(2^-3))/4)*y^4 = 0

-1/2*x^(1/8)*y^4 = 0 // : -1/2*y^4

x^(1/8) = 0

x = 0

x in (0:+oo)

(((-2*x^(2^-3))/4)*y^4)^-3 = 0

-8*x^(-3/8)*y^-12 = 0 // : -8*y^-12

x^(-3/8) = 0

x należy do O

x belongs to the empty set

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